| commit | 19c5e177c75bcc802f5ac1c6e5b2db1d64f2e280 | [log] [tgz] |
|---|---|---|
| author | Krzysztof Kosiński <[email protected]> | Thu Sep 22 01:30:58 2022 +0000 |
| committer | Automerger Merge Worker <[email protected]> | Thu Sep 22 01:30:58 2022 +0000 |
| tree | 1658cb90958498bab43d7ddd0aa2ef61be41ff5d | |
| parent | 8640dcfecb8596d172114e2ecba01f4887346c13 [diff] | |
| parent | 495307d16496c422c1bb8a869a0537cf4bd53ba7 [diff] |
Disable unused Python 2 variant. am: dffab708bc am: fea3b33a1d am: e47f54fcaf am: 421f2a7154 am: 495307d164 Original change: https://android-review.googlesource.com/c/platform/external/python/ipaddress/+/2221332 Change-Id: Ib4064815b3854dabc4dc8a92bb1cc375571ab5ec Signed-off-by: Automerger Merge Worker <[email protected]>
Python 3.3+'s ipaddress for Python 2.6, 2.7, 3.2.
This repository tracks the latest version from cpython, e.g. ipaddress from cpython 3.8 as of writing.
Note that just like in Python 3.3+ you must use character strings and not byte strings for textual IP address representations:
>>> from __future__ import unicode_literals >>> ipaddress.ip_address('1.2.3.4') IPv4Address(u'1.2.3.4')
or
>>> ipaddress.ip_address(u'1.2.3.4') IPv4Address(u'1.2.3.4')
but not:
>>> ipaddress.ip_address(b'1.2.3.4') Traceback (most recent call last): File "<stdin>", line 1, in <module> File "ipaddress.py", line 163, in ip_address ' a unicode object?' % address) ipaddress.AddressValueError: '1.2.3.4' does not appear to be an IPv4 or IPv6 address. Did you pass in a bytes (str in Python 2) instead of a unicode object?