| /* SPDX-License-Identifier: LGPL-2.1-or-later */ |
| /* |
| * Provides fixed-point logarithm operations. |
| * |
| * Copyright (C) 2006 Christoph Pfister ([email protected]) |
| */ |
| |
| #ifndef __LINUX_INT_LOG_H |
| #define __LINUX_INT_LOG_H |
| |
| #include <linux/types.h> |
| |
| /** |
| * intlog2 - computes log2 of a value; the result is shifted left by 24 bits |
| * |
| * @value: The value (must be != 0) |
| * |
| * to use rational values you can use the following method: |
| * |
| * intlog2(value) = intlog2(value * 2^x) - x * 2^24 |
| * |
| * Some usecase examples: |
| * |
| * intlog2(8) will give 3 << 24 = 3 * 2^24 |
| * |
| * intlog2(9) will give 3 << 24 + ... = 3.16... * 2^24 |
| * |
| * intlog2(1.5) = intlog2(3) - 2^24 = 0.584... * 2^24 |
| * |
| * |
| * return: log2(value) * 2^24 |
| */ |
| extern unsigned int intlog2(u32 value); |
| |
| /** |
| * intlog10 - computes log10 of a value; the result is shifted left by 24 bits |
| * |
| * @value: The value (must be != 0) |
| * |
| * to use rational values you can use the following method: |
| * |
| * intlog10(value) = intlog10(value * 10^x) - x * 2^24 |
| * |
| * An usecase example: |
| * |
| * intlog10(1000) will give 3 << 24 = 3 * 2^24 |
| * |
| * due to the implementation intlog10(1000) might be not exactly 3 * 2^24 |
| * |
| * look at intlog2 for similar examples |
| * |
| * return: log10(value) * 2^24 |
| */ |
| extern unsigned int intlog10(u32 value); |
| |
| #endif |