| // Issue #14893. Tests that casts from vectors don't behave strangely in the |
| // presence of the `_` type shorthand notation. |
| // |
| // Update: after a change to the way casts are done, we have more type information |
| // around and so the errors here are no longer exactly the same. |
| // |
| // Update: With PR #81479 some of the previously rejected cases are now allowed. |
| // New test cases added. |
| |
| struct X { |
| y: [u8; 2], |
| } |
| |
| fn main() { |
| let x1 = X { y: [0, 0] }; |
| |
| // No longer a type mismatch - the `_` can be fully resolved by type inference. |
| let p1: *const u8 = &x1.y as *const _; |
| let p1: *mut u8 = &x1.y as *mut _; |
| //~^ ERROR: casting `&[u8; 2]` as `*mut u8` is invalid |
| let t1: *const [u8; 2] = &x1.y as *const _; |
| let t1: *mut [u8; 2] = &x1.y as *mut _; |
| //~^ ERROR: casting `&[u8; 2]` as `*mut [u8; 2]` is invalid |
| let h1: *const [u8; 2] = &x1.y as *const [u8; 2]; |
| let t1: *mut [u8; 2] = &x1.y as *mut [u8; 2]; |
| //~^ ERROR: casting `&[u8; 2]` as `*mut [u8; 2]` is invalid |
| |
| let mut x1 = X { y: [0, 0] }; |
| |
| let p1: *mut u8 = &mut x1.y as *mut _; |
| let p2: *const u8 = &mut x1.y as *const _; |
| let t1: *mut [u8; 2] = &mut x1.y as *mut _; |
| let h1: *mut [u8; 2] = &mut x1.y as *mut [u8; 2]; |
| } |
