| error[E0597]: `c` does not live long enough |
| --> $DIR/shorter-tail-expr-lifetime.rs:10:5 |
| | |
| LL | let c = std::cell::RefCell::new(".."); |
| | - binding `c` declared here |
| LL | c.borrow().len() |
| | ^--------- |
| | | |
| | borrowed value does not live long enough |
| | a temporary with access to the borrow is created here ... |
| LL | } |
| | - |
| | | |
| | `c` dropped here while still borrowed |
| | ... and the borrow might be used here, when that temporary is dropped and runs the destructor for type `Ref<'_, &str>` |
| | |
| = note: the temporary is part of an expression at the end of a block; |
| consider forcing this temporary to be dropped sooner, before the block's local variables are dropped |
| help: for example, you could save the expression's value in a new local variable `x` and then make `x` be the expression at the end of the block |
| | |
| LL | let x = c.borrow().len(); x |
| | +++++++ +++ |
| |
| error: aborting due to 1 previous error |
| |
| For more information about this error, try `rustc --explain E0597`. |
